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-18+35x-16x^2=0
a = -16; b = 35; c = -18;
Δ = b2-4ac
Δ = 352-4·(-16)·(-18)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{73}}{2*-16}=\frac{-35-\sqrt{73}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{73}}{2*-16}=\frac{-35+\sqrt{73}}{-32} $
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